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NAG Toolbox: nag_specfun_kelvin_ber_vector (s19an)
Purpose
nag_specfun_kelvin_ber_vector (s19an) returns an array of values for the Kelvin function .
Syntax
Description
nag_specfun_kelvin_ber_vector (s19an) evaluates an approximation to the Kelvin function for an array of arguments , for .
Note: , so the approximation need only consider .
The function is based on several Chebyshev expansions:
For
,
For
,
where
,
,
and , , , and are expansions in the variable .
When is sufficiently close to zero, the result is set directly to .
For large , there is a danger of the result being totally inaccurate, as the error amplification factor grows in an essentially exponential manner; therefore the function must fail.
References
Abramowitz M and Stegun I A (1972) Handbook of Mathematical Functions (3rd Edition) Dover Publications
Parameters
Compulsory Input Parameters
- 1:
– double array
-
The argument of the function, for .
Optional Input Parameters
- 1:
– int64int32nag_int scalar
-
Default:
the dimension of the array
x.
, the number of points.
Constraint:
.
Output Parameters
- 1:
– double array
-
, the function values.
- 2:
– int64int32nag_int array
-
contains the error code for
, for
.
- No error.
- is too large for an accurate result to be returned. contains zero. The threshold value is the same as for in nag_specfun_kelvin_ber (s19aa), as defined in the Users' Note for your implementation.
- 3:
– int64int32nag_int scalar
unless the function detects an error (see
Error Indicators and Warnings).
Error Indicators and Warnings
Errors or warnings detected by the function:
Cases prefixed with W are classified as warnings and
do not generate an error of type NAG:error_n. See nag_issue_warnings.
- W
-
On entry, at least one value of
x was invalid.
Check
ivalid for more information.
-
-
Constraint: .
-
An unexpected error has been triggered by this routine. Please
contact
NAG.
-
Your licence key may have expired or may not have been installed correctly.
-
Dynamic memory allocation failed.
Accuracy
Since the function is oscillatory, the absolute error rather than the relative error is important. Let
be the absolute error in the result and
be the relative error in the argument. If
is somewhat larger than the
machine precision, then we have:
(provided
is within machine bounds).
For small
the error amplification is insignificant and thus the absolute error is effectively bounded by the
machine precision.
For medium and large , the error behaviour is oscillatory and its amplitude grows like . Therefore it is not possible to calculate the function with any accuracy when . Note that this value of is much smaller than the minimum value of for which the function overflows.
Further Comments
None.
Example
This example reads values of
x from a file, evaluates the function at each value of
and prints the results.
Open in the MATLAB editor:
s19an_example
function s19an_example
fprintf('s19an example results\n\n');
x = [0.1; 1; 2.5; 5; 10; 15; -1];
[f, ivalid, ifail] = s19an(x);
fprintf(' x ber(x) ivalid\n');
for i=1:numel(x)
fprintf('%12.3e%12.3e%5d\n', x(i), f(i), ivalid(i));
end
s19an example results
x ber(x) ivalid
1.000e-01 1.000e+00 0
1.000e+00 9.844e-01 0
2.500e+00 4.000e-01 0
5.000e+00 -6.230e+00 0
1.000e+01 1.388e+02 0
1.500e+01 -2.967e+03 0
-1.000e+00 9.844e-01 0
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