e04fy is an easy-to-use algorithm for finding an unconstrained minimum of a sum of squares of m nonlinear functions in n variables mn. No derivatives are required.
It is intended for functions which are continuous and which have continuous first and second derivatives (although it will usually work even if the derivatives have occasional discontinuities).

Syntax

C#
public static void e04fy(
	int m,
	int n,
	E04..::..E04FY_LSFUN1 lsfun1,
	double[] x,
	out double fsumsq,
	out int ifail
)
Visual Basic
Public Shared Sub e04fy ( _
	m As Integer, _
	n As Integer, _
	lsfun1 As E04..::..E04FY_LSFUN1, _
	x As Double(), _
	<OutAttribute> ByRef fsumsq As Double, _
	<OutAttribute> ByRef ifail As Integer _
)
Visual C++
public:
static void e04fy(
	int m, 
	int n, 
	E04..::..E04FY_LSFUN1^ lsfun1, 
	array<double>^ x, 
	[OutAttribute] double% fsumsq, 
	[OutAttribute] int% ifail
)
F#
static member e04fy : 
        m : int * 
        n : int * 
        lsfun1 : E04..::..E04FY_LSFUN1 * 
        x : float[] * 
        fsumsq : float byref * 
        ifail : int byref -> unit 

Parameters

m
Type: System..::..Int32
On entry: the number m of residuals, fix, and the number n of variables, xj.
Constraint: 1nm.
n
Type: System..::..Int32
On entry: the number m of residuals, fix, and the number n of variables, xj.
Constraint: 1nm.
lsfun1
Type: NagLibrary..::..E04..::..E04FY_LSFUN1
You must supply this method to calculate the vector of values fix at any point x. It should be tested separately before being used in conjunction with e04fy (see the E04 class).

A delegate of type E04FY_LSFUN1.

x
Type: array<System..::..Double>[]()[][]
An array of size [n]
On entry: x[j-1] must be set to a guess at the jth component of the position of the minimum, for j=1,2,,n.
On exit: the lowest point found during the calculations. Thus, if ifail=0 on exit, x[j-1] is the jth component of the position of the minimum.
fsumsq
Type: System..::..Double%
On exit: the value of the sum of squares, Fx, corresponding to the final point stored in x.
ifail
Type: System..::..Int32%
On exit: ifail=0 unless the method detects an error or a warning has been flagged (see [Error Indicators and Warnings]).

Description

e04fy is essentially identical to the method LSNDN1 in the NPL Algorithms Library. It is applicable to problems of the form
MinimizeFx=i=1mfix2
where x=x1,x2,,xnT and mn. (The functions fix are often referred to as ‘residuals’.)
You must supply a method to evaluate functions fix at any point x.
From a starting point supplied by you, a sequence of points is generated which is intended to converge to a local minimum of the sum of squares. These points are generated using estimates of the curvature of Fx.

References

Gill P E and Murray W (1978) Algorithms for the solution of the nonlinear least squares problem SIAM J. Numer. Anal. 15 977–992

Error Indicators and Warnings

Note: e04fy may return useful information for one or more of the following detected errors or warnings.
Errors or warnings detected by the method:
ifail=1
On entry,n<1,
orm<n,
orlw<7×n+n×n+2×m×n+3×m+n×n-1/2, when n>1,
orlw<9+5×m, when n=1.
ifail=2
There have been 400×n calls of lsfun1, yet the algorithm does not seem to have converged. This may be due to an awkward function or to a poor starting point, so it is worth restarting e04fy from the final point held in x.
ifail=3
The final point does not satisfy the conditions for acceptance as a minimum, but no lower point could be found.
ifail=4
An auxiliary method has been unable to complete a singular value decomposition in a reasonable number of sub-iterations.
ifail=5
ifail=6
ifail=7
ifail=8
There is some doubt about whether the point xx found by e04fy is a minimum of Fx. The degree of confidence in the result decreases as ifail increases. Thus, when ifail=5, it is probable that the final x gives a good estimate of the position of a minimum, but when ifail=8 it is very unlikely that the method has found a minimum.
ifail=-9000
An error occured, see message report.
ifail=-8000
Negative dimension for array value
ifail=-6000
Invalid Parameters value
If you are not satisfied with the result (e.g., because ifail lies between 3 and 8), it is worth restarting the calculations from a different starting point (not the point at which the failure occurred) in order to avoid the region which caused the failure. Repeated failure may indicate some defect in the formulation of the problem.

Accuracy

If the problem is reasonably well scaled and a successful exit is made, then, for a computer with a mantissa of t decimals, one would expect to get about t/2-1 decimals accuracy in the components of x and between t-1 (if Fx is of order 1 at the minimum) and 2t-2 (if Fx is close to zero at the minimum) decimals accuracy in Fx.

Parallelism and Performance

None.

Further Comments

The number of iterations required depends on the number of variables, the number of residuals and their behaviour, and the distance of the starting point from the solution. The number of multiplications performed per iteration of e04fy varies, but for mn is approximately n×m2+On3. In addition, each iteration makes at least n+1 calls of lsfun1. So, unless the residuals can be evaluated very quickly, the run time will be dominated by the time spent in lsfun1.
Ideally, the problem should be scaled so that the minimum value of the sum of squares is in the range 0,+1, and so that at points a unit distance away from the solution the sum of squares is approximately a unit value greater than at the minimum. It is unlikely that you will be able to follow these recommendations very closely, but it is worth trying (by guesswork), as sensible scaling will reduce the difficulty of the minimization problem, so that e04fy will take less computer time.
When the sum of squares represents the goodness-of-fit of a nonlinear model to observed data, elements of the variance-covariance matrix of the estimated regression coefficients can be computed by a subsequent call to (E04YCF not in this release), using information returned in segments of the workspace array w. See (E04YCF not in this release) for further details.

Example

This example finds least squares estimates of x1, x2 and x3 in the model
y=x1+t1x2t2+x3t3
using the 15 sets of data given in the following table.
y0t10t20t300.141.015.01.00.182.014.02.00.223.013.03.00.254.012.04.00.295.011.05.00.326.010.06.00.357.09.07.00.398.08.08.00.379.07.07.00.5810.06.06.00.7311.05.05.00.9612.04.04.01.3413.03.03.02.1014.02.02.04.3915.01.01.0
The program uses 0.5,1.0,1.5 as the initial guess at the position of the minimum.

Example program (C#): e04fye.cs

Example program data: e04fye.d

Example program results: e04fye.r

See Also