D03PFF Example Program Results


 Example 1


 Number of mesh points used =  101
 Relative tolerance used    =  0.100E-03
 Absolute tolerance used    =  0.100E-04

     t         x        Approx u    Exact u     Approx v    Exact v

  0.100      0.0000      1.0615      1.0613     -0.0155     -0.0150
             0.2000      0.9892      0.9891     -0.0953     -0.0957
             0.4000      1.0826      1.0826      0.1180      0.1178
             0.6000      1.7001      1.7001     -0.0751     -0.0746
             0.8000      2.3959      2.3966     -0.2453     -0.2458
             1.0000      2.1029      2.1025      0.3760      0.3753

  0.200      0.0000      1.0957      1.0956      0.0368      0.0370
             0.2000      1.0808      1.0811      0.1826      0.1828
             0.4000      1.1102      1.1100     -0.2935     -0.2938
             0.6000      1.6461      1.6454     -1.2921     -1.2908
             0.8000      1.7913      1.7920     -0.8510     -0.8525
             1.0000      2.2050      2.2050     -0.4222     -0.4221

 Number of time steps           (nearest 5)  =     55
 Number of function evaluations (nearest 50) =    250
 Number of Jacobian evaluations (nearest 10) =     10
 Number of iterations           (nearest 50) =    150


 Example 2


 Number of mesh points used =  151
 Relative tolerance used    =  0.100E-04
 Absolute tolerance used    =  0.100E-04

 x            -1.0000  -0.9600  -0.5200   0.0000   0.4800   0.9600   1.0000
 u(t= 1.000)   3.0000   3.6221   3.8087   4.0000   4.1766   4.3779   5.0000
 u(t=10.000)   3.0000   3.9592   4.0000   4.0000   4.0000   4.0408   5.0000

 Number of time steps           (nearest 5)  =    505
 Number of function evaluations (nearest 50) =   1200
 Number of Jacobian evaluations (nearest 10) =     30
 Number of iterations           (nearest 50) =   1050