nag::ad::d02pt Tangent Example Program Results

 Cost of the integration in evaluations of f is 892

 Derivatives calculated: First order tangents
 Computational mode    : algorithmic

 Solution computed with required tolerance 1.000000000000e-04
 y1 = 3.044899135339e-05
 y2 = 9.996811982879e-01

 Sum of all Jacobian elements of solution vector y w.r.t. initial values:
 sum_ij [dy/dy0]_ij = 1.999494141100e+00