NAG Library Manual, Mark 30
Interfaces:  FL   CL   CPP   AD 

NAG FL Interface Introduction
Example description

 D02TZF Example Program Results



 Tolerance =  0.1E-04  EPS =  0.100E-03

 Used a mesh of   25 points
 Maximum error =   0.21E-05  in interval   16 for component    1

 Solution and derivative at every second point:
      x        u          u'
   0.0000   -0.33333    1.00000
   0.0750   -0.25833    1.00000
   0.1500   -0.18333    1.00000
   0.2250   -0.10833    1.00002
   0.3000   -0.03332    1.00372
   0.4000   -0.00001    0.00084
   0.5000   -0.00000    0.00000
   0.6000    0.00001    0.00084
   0.7000    0.03332    1.00372
   0.7750    0.10833    1.00002
   0.8500    0.18333    1.00000
   0.9250    0.25833    1.00000
   1.0000    0.33333    1.00000


 Tolerance =  0.1E-04  EPS =  0.100E-04

 Used a mesh of   49 points
 Maximum error =   0.21E-05  in interval   32 for component    1

 Solution and derivative at every second point:
      x        u          u'
   0.0000   -0.33333    1.00014
   0.0375   -0.29583    1.00018
   0.0750   -0.25833    1.00022
   0.1125   -0.22083    1.00029
   0.1500   -0.18333    1.00040
   0.1875   -0.14583    1.00059
   0.2250   -0.10833    1.00098
   0.2625   -0.07083    1.00202
   0.3000   -0.03333    1.00745
   0.3500   -0.00001    0.00354
   0.4000   -0.00000    0.00000
   0.4500   -0.00000    0.00000
   0.5000    0.00000   -0.00000
   0.5500    0.00000    0.00000
   0.6000    0.00000    0.00000
   0.6500    0.00001    0.00354
   0.7000    0.03333    1.00745
   0.7375    0.07083    1.00202
   0.7750    0.10833    1.00098
   0.8125    0.14583    1.00059
   0.8500    0.18333    1.00040
   0.8875    0.22083    1.00029
   0.9250    0.25833    1.00022
   0.9625    0.29583    1.00018
   1.0000    0.33333    1.00014