NAG Library Manual, Mark 30
Interfaces:  FL   CL   CPP   AD 

NAG FL Interface Introduction
Example description

 C02AAF Example Program Results
 
 Basic Problem
 
  i    z                      conv  berr      cond
 -----------------------------------------------------
  1  (  6.53E-03,  7.42E-03)    5  < epsilon  4.84E+00
  2  ( -6.93E-03, -7.44E-03)    5  < epsilon  4.95E+00
  3  ( -2.43E+01, -4.86E+00)    3  < epsilon  1.13E+01
  4  (  1.47E+01, -1.66E+01)    3  < epsilon  9.99E+00
  5  (  5.25E+00,  2.27E+01)    3  < epsilon  1.06E+01