D02PGF Example Program Results
Calculation with TOL = 0.1E-04
t y1 y2
0.000 0.0000 1.0000
0.100 0.0998 0.9950
0.200 0.1987 0.9801
0.300 0.2955 0.9553
0.400 0.3894 0.9211
0.500 0.4794 0.8776
0.600 0.5646 0.8253
0.700 0.6442 0.7648
0.800 0.7174 0.6967
0.900 0.7833 0.6216
1.000 0.8415 0.5403
1.100 0.8912 0.4536
1.200 0.9320 0.3624
1.300 0.9636 0.2675
1.400 0.9854 0.1700
1.500 0.9975 0.0707
Component 2 has a root at t = 1.5708
1.600 0.9996 -0.0292
1.700 0.9917 -0.1288
1.800 0.9738 -0.2272
1.900 0.9463 -0.3233
2.000 0.9093 -0.4161
2.100 0.8632 -0.5048
2.200 0.8085 -0.5885
2.300 0.7457 -0.6663
2.400 0.6755 -0.7374
2.500 0.5985 -0.8011
2.600 0.5155 -0.8569
2.700 0.4274 -0.9041
2.800 0.3350 -0.9422
2.900 0.2392 -0.9710
3.000 0.1411 -0.9900
3.100 0.0416 -0.9991
Component 1 has a root at t = 3.1416
3.200 -0.0584 -0.9983
3.300 -0.1577 -0.9875
3.400 -0.2555 -0.9668
3.500 -0.3508 -0.9365
3.600 -0.4425 -0.8968
3.700 -0.5298 -0.8481
3.800 -0.6119 -0.7910
3.900 -0.6878 -0.7259
4.000 -0.7568 -0.6536
4.100 -0.8183 -0.5748
4.200 -0.8716 -0.4903
4.300 -0.9162 -0.4008
4.400 -0.9516 -0.3073
4.500 -0.9775 -0.2108
4.600 -0.9937 -0.1122
4.700 -0.9999 -0.0124
Component 2 has a root at t = 4.7124
4.800 -0.9962 0.0875
4.900 -0.9825 0.1865
5.000 -0.9589 0.2837
5.100 -0.9258 0.3780
5.200 -0.8835 0.4685
5.300 -0.8323 0.5544
5.400 -0.7728 0.6347
5.500 -0.7055 0.7087
5.600 -0.6313 0.7756
5.700 -0.5507 0.8347
5.800 -0.4646 0.8855
5.900 -0.3739 0.9275
6.000 -0.2794 0.9602
6.100 -0.1822 0.9833
6.200 -0.0831 0.9965
Component 1 has a root at t = 6.2832
Cost of the integration in evaluations of F is 356