NAG Library Manual, Mark 30.3
Interfaces:  FL   CL   CPP   AD 

NAG CL Interface Introduction
Example description

nag_roots_contfn_brent_rcomm (c05azc) Example Program Results

 Iterations
 x =  0.00000   fx =    1.0000e+00   ind =  2
 x =  1.00000   fx =   -6.3212e-01   ind =  3
 x =  0.61270   fx =   -7.0814e-02   ind =  4
 x =  0.56707   fx =    1.1542e-04   ind =  4
 x =  0.56714   fx =   -9.4481e-07   ind =  4
 x =  0.56713   fx =    1.4727e-05   ind =  4
 x =  0.56714   fx =   -9.4481e-07   ind =  4

 Solution
 x =  0.56714   y =  0.56713