NAG Library Manual, Mark 30.1
Interfaces:  FL   CL   CPP   AD 

NAG FL Interface Introduction
Example description

 F11JPF Example Program Results
 Solution of linear system
 (      0.1000E+01,      0.9000E+01)
 (      0.2000E+01,     -0.8000E+01)
 (      0.3000E+01,      0.7000E+01)
 (      0.4000E+01,     -0.6000E+01)
 (      0.5000E+01,      0.5000E+01)
 (      0.6000E+01,     -0.4000E+01)
 (      0.7000E+01,      0.3000E+01)
 (      0.8000E+01,     -0.2000E+01)
 (      0.9000E+01,      0.1000E+01)