D01PA_T1W_F Example Program Results Maxord Estimated Estimated Integrand value accuracy evaluations 1 0.25816 0.258E+00 1 2 0.25011 0.806E-02 5 3 0.25000 0.107E-03 15 4 0.25000 0.410E-06 35 5 0.25000 0.173E-08 70 Derivatives calculated: First order tangents Computational mode : algorithmic Solution, I = 0.25000 Derivatives w.r.t vertices: i j d/dv(i,j) 1 1 -0.2343E+00 1 2 -0.2343E+00 1 3 -0.2343E+00 2 1 0.2448E+00 2 2 -0.5218E-02 2 3 -0.5218E-02 3 1 -0.5218E-02 3 2 0.2448E+00 3 3 -0.5218E-02 4 1 -0.5218E-02 4 2 -0.5218E-02 4 3 0.2448E+00