NAG Library Manual, Mark 28.6
Interfaces:  FL   CL   CPP   AD 

NAG AD Library Introduction
Example description

 nag::ad::e04gb Tangent over Tangent Example Program Results

 Sum of squares =   8.214877306579e-03
 Solution point =   8.241055980977e-02  1.133036092052e+00  2.343695178713e+00

 Residuals :
 -5.881090849547e-03
 -2.653450007297e-04
  2.746922657645e-04
  6.541540934042e-03
 -8.229908168291e-04
 -1.299494717187e-03
 -4.463111506844e-03
 -1.996295366571e-02
  8.221604248415e-02
 -1.821196264937e-02
 -1.481116983629e-02
 -1.470998061668e-02
 -1.120799858399e-02
 -4.204034518610e-03
  6.807857677526e-03


 Derivatives calculated: Second order tangents

 Sum of Hessian elements of sum of squares fsumsq w.r.t. parameters y and t:
 sum_i [d2fsumsq/dall2]_ij = 1.563059505366e+00

 Sum of Hessian elements of solution points x w.r.t. parameters y and t:
 sum_ij [d2x/dall2]_ij = 6.902927113557e+00