NAG Library Manual, Mark 28.6
Interfaces:  FL   CL   CPP   AD 

NAG AD Library Introduction
Example description

 nag::ad::e04fc Tangent over Tangent Example Program Results

 Sum of squares =   8.214877306579e-03
 Solution point =   8.241056010522e-02  1.133036105199e+00  2.343695165997e+00

 Residuals :
 -5.881091047379e-03
 -2.653454565346e-04
  2.746917200908e-04
  6.541540419146e-03
 -8.229912142825e-04
 -1.299494935154e-03
 -4.463111501296e-03
 -1.996295340591e-02
  8.221604273377e-02
 -1.821196241333e-02
 -1.481116961926e-02
 -1.470998042816e-02
 -1.120799844300e-02
 -4.204034472674e-03
  6.807857438304e-03


 Derivatives calculated: Second order tangents

 Sum of Hessian elements of sum of squares fsumsq w.r.t. parameters y and t:
 sum_ij [d2fsumsq/dall2]_ij = 1.563059505366e+00

 Sum of Hessian elements of solution points x w.r.t. parameters y and t:
 sum_ij [d2x/dall2]_ij = 6.902926807059e+00