D02PE_T2W_F Example Program Results

 Calculation with TOL =  1.0E-04

    t         y1        y2

  0.000     0.000     1.000
  0.785     0.707     0.707
  1.571     1.000    -0.000
  2.356     0.707    -0.707
  3.142    -0.000    -1.000
  3.927    -0.707    -0.707
  4.712    -1.000     0.000
  5.498    -0.707     0.707
  6.283     0.000     1.000

 Cost of the integration in evaluations of F is   892

  Derivatives calculated: Second order tangents
  Computational mode    : algorithmic

  Derivatives:
  d^2y(t)/dy0^2  =  0.75393E-03
  d^2y(t)/dy0'^2 = -0.30179E-21