D02PE_T2W_F Example Program Results Calculation with TOL = 1.0E-04 t y1 y2 0.000 0.000 1.000 0.785 0.707 0.707 1.571 1.000 -0.000 2.356 0.707 -0.707 3.142 -0.000 -1.000 3.927 -0.707 -0.707 4.712 -1.000 0.000 5.498 -0.707 0.707 6.283 0.000 1.000 Cost of the integration in evaluations of F is 892 Derivatives calculated: Second order tangents Computational mode : algorithmic Derivatives: d^2y(t)/dy0^2 = 0.75393E-03 d^2y(t)/dy0'^2 = -0.30179E-21