NAG Library Manual, Mark 27.2
Interfaces:  FL   CL   CPP   AD 

NAG AD Library Introduction
Example description
/* C05QD_P0W_F C++ Header Example Program.
 *
 * Copyright 2021 Numerical Algorithms Group.
 * Mark 27.2, 2021.
 */

#include <iostream>
#include <math.h>
#include <nag.h>
#include <nagad.h>
#include <nagx02.h>
#include <nagx04.h>
#include <stdio.h>
#include <string>
using namespace std;

int main(void)
{
  // Scalars
  int           exit_status = 0;
  const Integer mode = 2, n = 7;

  cout << "C05QD_P0W_F C++ Header Example Program Results\n\n";

  // problem parameters and starting value
  double ruser[5], x[7];

  ruser[0] = -1.0;
  ruser[1] = 3.0;
  ruser[2] = -2.0;
  ruser[3] = -2.0;
  ruser[4] = -1.0;

  for (int i = 0; i < n; ++i)
    {
      x[i] = -1.0;
    }

  Integer ifail     = 0;
  void *  ad_handle = 0;
  double  diag[n], epsfcn, fjac[n * n], factor, fvec[n], qtf[n],
      r[n * (n + 1) / 2], rwsav[4 * n + 10], xtol;
  Integer irevcm, iwsav[17], ml, mu;

  xtol   = sqrt(X02AJC);
  factor = 100.;
  for (int i = 0; i < n; ++i)
    {
      diag[i] = 1.;
    }
  ml     = 1;
  mu     = 1;
  epsfcn = 0.;

  irevcm = 0;

  do
    {
      ifail = 0;
      nag::ad::c05qd(ad_handle, irevcm, n, x, fvec, xtol, ml, mu, epsfcn, mode,
                     diag, factor, fjac, r, qtf, iwsav, rwsav, ifail);

      switch (irevcm)
        {
        case 1:
          // Monitoring exit
          continue;
        case 2:
          for (int i = 0; i < n; ++i)
            {
              fvec[i] = (ruser[1] + ruser[2] * x[i]) * x[i] - ruser[4];
            }
          for (int i = 1; i < n; ++i)
            {
              fvec[i] = fvec[i] + ruser[0] * x[i - 1];
            }
          for (int i = 0; i < n - 1; ++i)
            {
              fvec[i] = fvec[i] + ruser[3] * x[i + 1];
            }
          break;
        }
    }
  while (irevcm != 0);

  cout.setf(ios::scientific, ios::floatfield);
  cout.precision(4);
  cout << "           Solution:\n";
  for (int i = 0; i < n; ++i)
    {
      cout.width(10);
      cout << i + 1;
      cout.width(20);
      cout << x[i] << endl;
    }

  return exit_status;
}