Example description
/* E04NE_P0W_F C++ Header Example Program.
 *
 * Copyright 2020 Numerical Algorithms Group.
 * Mark 27.1, 2020.
 */

#include <nag.h>
#include <nagad.h>
#include <stdio.h>
#include <math.h>
#include <iostream>
#include <string>
using namespace std;

int main(void)
{
  // Scalars
  int               exit_status = 0;

  cout << "E04NE_P0W_F C++ Header Example Program Results\n\n";

  Integer ifail = 0;
  void    *ad_handle = 0;

  // Skip first line of data file
  string mystr;
  getline (cin, mystr);

  // Read problem sizes
  Integer m, n, nclin;
  cin >> m;
  cin >> n;
  cin >> nclin;

  Integer liwork = n;
  Integer lda = m, sda = n, ldc = nclin, lb = n + nclin;
  Integer lwork;

  lwork = 9*n;
  if (nclin>0) {
    lwork = lwork + 2*n*n + 6*nclin;
  }
  double   *a=0, *b=0, *bl=0, *bu=0, *c=0;
  double   *cvec=0, *clamda=0, *work=0, *x=0, *rwsav=0;
  Integer  *istate=0, *iwork=0, *iwsav=0, *kx=0;
  logical  *lwsav=0;
  a      = new double  [lda*sda];
  b      = new double  [m];
  bl     = new double  [lb];
  bu     = new double  [lb];
  c      = new double  [nclin*n];
  clamda = new double  [lb];
  x      = new double  [n];
  kx     = new Integer [n];
  work   = new double  [lwork];
  rwsav  = new double  [475];
  lwsav  = new logical [120];
  istate = new Integer [lb];
  iwork  = new Integer [liwork];
  iwsav  = new Integer [610];

  // Read problem parameters and register for differentiation
  for (int i=0; i<m; i++) {
    for (int j=0; j<n; j++) {
      Integer k = i + j*m;
      cin >> a[k];
    }
  }
  for (int i=0; i<m; i++) {
    cin >> b[i];
  }
  for (int i=0; i<nclin; i++) {
    for (int j=0; j<n; j++) {
      Integer k = i + j*nclin;
      cin >> c[k];
    }
  }
  for (int i=0; i<lb; i++) {
    cin >> bl[i];
  }
  for (int i=0; i<lb; i++) {
    cin >> bu[i];
  }
  for (int i=0; i<n; i++) {
    cin >> x[i];
  }

  // Initialize sav arrays
  ifail = 0;
  char cwsav[1];
  e04wb_p0w_f_("E04NCA",cwsav,1,lwsav,120,iwsav,610,rwsav,475,ifail,6,1);
  // Set option via string
  e04ne_p0w_f_("Print Level = -1",lwsav,iwsav,rwsav,16);
    
  // Solve the problem
  Integer iter;
  double  obj;
  ifail = -1;
  e04nc_p0w_f_(ad_handle,m,n,nclin,ldc,lda,c,bl,bu,cvec,istate,kx,x,a,
               b,iter,obj,clamda,iwork,liwork,work,lwork,lwsav,iwsav,rwsav,
               ifail);
    
  // Primal results
  cout.setf(ios::scientific,ios::floatfield);
  if (ifail==0 || ifail>1) {
    cout.precision(4);
    cout << "\n Optimal objective function value = ";
    cout.width(12); cout << obj << endl;
    cout << "\n Solution point: " << endl;
    for (int i=0; i<n; i++) {
      cout.width(8); cout << i;
      cout.width(12); cout << x[i] << endl;
    }
  } else {
    cout << "e04nc_p0w_f_ failed with ifail = " << ifail << endl;
  }
  
  delete [] a;
  delete [] b;
  delete [] bl;
  delete [] bu;
  delete [] c;
  delete [] clamda;
  delete [] x;
  delete [] kx;
  delete [] work;
  delete [] rwsav;
  delete [] lwsav;
  delete [] istate;
  delete [] iwork;
  delete [] iwsav;
  return exit_status;
}