D02PE_T1W_F C++ Header Example Program Results


  Calculation with tol = 0.0001

    t         y1        y2
 0.000     0.000     1.000
 0.785     0.707     0.707
 1.571     1.000    -0.000
 2.356     0.707    -0.707
 3.142    -0.000    -1.000
 3.927    -0.707    -0.707
 4.712    -1.000     0.000
 5.498    -0.707     0.707
 6.283     0.000     1.000

 Cost of the integration in evaluations of f is 892

 Derivatives calculated: First order tangents
 Computational mode    : algorithmic

 Derivatives: (solution w.r.t. initial values)
 dy(t)/dy0  =  9.99656e-01
 dy(t)/dy0' =  3.04490e-05