NAG Toolbox: nag_ode_dae_dassl_cont (d02mc)

function d02mc_example


fprintf('d02mc example results\n\n');

% Initialize the problem, specifying that the Jacobian is to be
% evaluated analytically using the provided routine jac.

neq    = int64(3);
maxord = int64(5);
jceval = 'Analytic';
hmax   = 0;
h0     = 0;
itol   = int64(1);
lcom   = int64(200);
[icom, com, ifail] = d02mw(neq, maxord, jceval, hmax, h0, itol, lcom);

% Specify that the Jacobian is banded
mu = int64(2);
ml = int64(1);
[icom, ifail] = d02np(neq, ml, mu, icom);


% Set initial values
rtol = [1e-3; 1e-3; 1e-3];
atol = [1e-6; 1e-6; 1e-6];
y    = [1; 0; 0];
ydot = zeros(neq,1);
t    = 0;
tout = 0.02;

% Use the user parameter to pass the band dimensions through to jac.
% An alternative would be to hard code values for ml and mu in jac.
user = {ml, mu};

fprintf('\n    t            y(1)        y(2)        y(3)   \n');
fprintf(' %8.4f   %12.6f %12.6f %12.6f\n', t, y);

itask = int64(0);
% Obtain the solution at 5 equally spaced values of T.
for j = 1:5
  if ifail == 0
    [t, y, ydot, rtol, atol, itask, icom, com, user, ifail] = ...
      d02ne(t, tout, ...
            y, ydot, rtol, atol, itask, @res, @jac, icom, com, 'user', user);
    fprintf(' %8.4f   %12.6f %12.6f %12.6f\n', t, y);
    tout = tout + 0.02;
    icom = d02mc(icom);
  end
end

fprintf('\nThe integrator completed task, ITASK = %d\n', itask);



function [pd, user] = jac(neq, t, y, ydot, pd, cj, user)
  ml = user{1};
  mu = user{2};

  stride = 2*ml+mu+1;
  % Main diagonal pdfull(i,i), i=1,neq
  md = mu + ml + 1;
  pd(md) = -0.04 - cj;
  pd(md+stride) = -1.0e4*y(3) - 6.0e7*y(2) - cj;
  pd(md+2*stride) = -cj;
  % 1 sub-diagonal pdfull(i+1:i), i=1,neq-1
  ms = md + 1;
  pd(ms) = 0.04;
  pd(ms+stride) = 6.0e7*y(2);
  % First super-diagonal pdfull(i-1,i), i=2, neq
  ms = md - 1;
  pd(ms+stride) = 1.0e4*y(3);
  pd(ms+2*stride) = -1.0e4*y(2);
  % Second super-diagonal pdfull(i-2,i), i=3, neq
  ms = md - 2;
  pd(ms+2*stride) = 1.0e4*y(2);


function [r, ires, user] = res(neq, t, y, ydot, ires, user)
  r = zeros(neq, 1);
  r(1) = -0.04*y(1) + 1.0e4*y(2)*y(3)                   - ydot(1);
  r(2) =  0.04*y(1) - 1.0e4*y(2)*y(3) - 3.0e7*y(2)*y(2) - ydot(2);
  r(3) =                                3.0e7*y(2)*y(2) - ydot(3);

d02mc example results


    t            y(1)        y(2)        y(3)   
   0.0000       1.000000     0.000000     0.000000
   0.0200       0.999204     0.000036     0.000760
   0.0400       0.998415     0.000036     0.001549
   0.0600       0.997631     0.000036     0.002333
   0.0800       0.996852     0.000036     0.003112
   0.1000       0.996080     0.000036     0.003884

The integrator completed task, ITASK = 3