E04JCF Example Program Results

    New RHO =  1.00000E-02, number of function evaluations =              25
    Current function value =  4.09399E+00
    The corresponding X is:
      0.16011E+01 -0.10360E+00  0.45113E+00  0.10233E+01

    New RHO =  1.00000E-03, number of function evaluations =              67
    Current function value =  2.43397E+00
    The corresponding X is:
      0.10000E+01 -0.85974E-01  0.40674E+00  0.10000E+01

    New RHO =  1.00000E-04, number of function evaluations =              77
    Current function value =  2.43379E+00
    The corresponding X is:
      0.10000E+01 -0.85233E-01  0.40934E+00  0.10000E+01

    New RHO =  1.00000E-05, number of function evaluations =              81
    Current function value =  2.43379E+00
    The corresponding X is:
      0.10000E+01 -0.85233E-01  0.40934E+00  0.10000E+01

    New RHO =  1.00000E-06, number of function evaluations =              91
    Current function value =  2.43379E+00
    The corresponding X is:
      0.10000E+01 -0.85233E-01  0.40930E+00  0.10000E+01

 Successful exit from E04JCF.
 Function value at lowest point found =  2.43379E+00
 The corresponding X is:
    0.10000E+01 -0.85232E-01  0.40930E+00  0.10000E+01