D01PA_T1W_F Example Program Results
  Maxord   Estimated      Estimated         Integrand
            value         accuracy        evaluations
    1      0.25816       0.258E+00              1
    2      0.25011       0.806E-02              5
    3      0.25000       0.107E-03             15
    4      0.25000       0.410E-06             35
    5      0.25000       0.173E-08             70

  Derivatives calculated: First order tangents
  Computational mode    : algorithmic

  Solution, I =      0.25000
  Derivatives w.r.t vertices:
   i   j   d/dv(i,j)
   1   1  -0.2343E+00
   1   2  -0.2343E+00
   1   3  -0.2343E+00
   2   1   0.2448E+00
   2   2  -0.5218E-02
   2   3  -0.5218E-02
   3   1  -0.5218E-02
   3   2   0.2448E+00
   3   3  -0.5218E-02
   4   1  -0.5218E-02
   4   2  -0.5218E-02
   4   3   0.2448E+00